MELU-105 · Lesson 6 of 12 · 26 min
Air conditioning and refrigeration equipment
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The Copper Kettle's two new rooftop units were craned onto the roof on a windy Tuesday, and Dana climbed up with Tyler to read the nameplates before they ran the circuits. Tyler reached for the motor tables out of habit, and Dana stopped him for the second time that month. Air-conditioning and refrigerating equipment with hermetic compressors has its own article, Article 440, and the nameplate on the unit, not the motor tables, sets the circuit. The unit's manufacturer has already done the motor calculation and printed the results: minimum circuit ampacity and maximum overcurrent protection. The electrician's job is to read those numbers correctly and meet the disconnect and receptacle rules around the unit.
This lesson covers Article 440: why hermetic compressors are treated differently, the rated-load current and branch-circuit selection current, how the minimum circuit ampacity and maximum overcurrent protection on the nameplate are used, the disconnect rules, the service receptacle requirement, and room air conditioners. It ends with how Article 440 equipment is added to feeder calculations.
Why hermetic compressors are different
In a hermetic refrigerant motor-compressor, the motor and compressor are sealed together inside a welded shell and cooled by the refrigerant itself. The motor's current depends on the refrigerant pressures, which depend on the weather and the load on the system, so a horsepower rating does not describe it well. Article 440 replaces horsepower with currents marked by the manufacturer. Section 440.3 explains how Article 440 relates to Article 430: Article 440 adds to or amends the motor rules for equipment with a hermetic compressor, and Article 430 still applies to the unit's other motors, such as fans, where Article 440 does not say otherwise.
Rated-load current and branch-circuit selection current
Two currents on an Article 440 nameplate matter. The rated-load current (RLA) is the current of the compressor when it runs at its rated load, determined by the manufacturer. Some compressors also carry a branch-circuit selection current (BCSC), which is higher than the rated-load current and is marked when the compressor's protective device allows it to run at a higher continuous current. Section 440.4 and the related definitions require the selection current, where marked, to be used instead of the rated-load current when sizing the conductors, the controller, the disconnect and the short-circuit protection. On an exam, if both currents appear, use the selection current.
The unit nameplate also lists the fan motors' full-load currents, and for packaged equipment it lists two results that combine everything: the minimum circuit ampacity (MCA) and the maximum overcurrent protective device rating (MOCP, sometimes printed as maximum fuse or maximum breaker size). Section 440.4(B) requires these markings on multimotor and combination-load equipment, and the installer uses them directly.
How the manufacturer's numbers are calculated
The minimum circuit ampacity follows the same idea as 430.24 for several motors. Section 440.33 sets the conductor ampacity for a circuit supplying a compressor with other loads at 125% of the largest motor-compressor current (rated-load or selection current, whichever is larger), plus the other motor and load currents. For a single compressor alone, 440.32 sets the conductor ampacity at 125% of the rated-load current or selection current, whichever is greater. Knowing this lets you check a nameplate, and exam questions sometimes ask you to calculate the minimum circuit ampacity from the component currents.
Worked problem
Checking the Copper Kettle unit's MCA
The rooftop unit nameplate shows a compressor RLA of 28.0 A (no BCSC), a condenser fan of 1.9 A and an indoor blower of 6.4 A. Calculate the minimum circuit ampacity.
Show solution
- Largest motor-compressor at 125%: 1.25 × 28.0 = 35.0 A.
- Other motors: 1.9 + 6.4 = 8.3 A.
- Minimum circuit ampacity: 35.0 + 8.3 = 43.3 A.
Answer: 43.3 A, matching the nameplate.
The maximum overcurrent protection follows 440.22. For a single compressor, the branch-circuit short-circuit and ground-fault device may not exceed 175% of the rated-load or selection current, and it may be increased to not more than 225% where the 175% device will not carry the starting current. For equipment with several motors, the device is based on the largest compressor's current at those percentages plus the other loads. Manufacturers do this calculation and round according to the article's rules; the result is the MOCP on the nameplate. Section 440.4(B) and 110.3(B) make that marked value a limit: the installed fuse or breaker may not exceed it.
Worked problem
Limits for the Copper Kettle compressor
Find 175% and 225% of the 28.0 A compressor RLA.
Show solution
- 175%: 1.75 × 28.0 = 49.0 A.
- 225%: 2.25 × 28.0 = 63.0 A.
- With the fan and blower currents added under the multimotor rule, the manufacturer arrived at a marked MOCP of 70 A.
Answer: 49.0 A and 63.0 A for the compressor alone; the nameplate MOCP of 70 A governs the installed device.
| Nameplate value | What you size from it | Rule |
|---|---|---|
| Minimum circuit ampacity (MCA) | Branch circuit conductors: ampacity at least the MCA | 440.33, 440.4(B), 110.3(B) |
| Maximum overcurrent protection (MOCP) | Fuse or breaker: not larger than the MOCP | 440.22, 440.4(B), 110.3(B) |
| Rated-load current (RLA) or BCSC | Disconnect rating (with 115%) | 440.12 |
| Locked-rotor current (LRA) | Disconnect horsepower equivalent | 440.12 |
Choosing the conductor and breaker in practice
With MCA 43.3 amperes and MOCP 70 amperes, Dana's circuit choice was straightforward. The conductors must have an ampacity of at least 43.3 amperes at the terminal temperature rating, so a conductor with a 75 °C ampacity of about 50 amperes works if the unit's terminals are rated 75 °C. The breaker may be anything up to 70 amperes that will carry the starting current, and must be of the type the nameplate allows; many nameplates say "maximum fuse or HACR breaker", and the installed device must match that wording. Ray usually installs the MOCP value or one size below it to avoid nuisance trips. A 70-ampere breaker on conductors rated about 50 amperes is permitted here for the same reason as in Lesson 3: the compressor's own protection handles overload.
Two exam traps hide in this step. The first is sizing the conductor to the MOCP instead of the MCA; the conductor needs only the MCA. The second is installing a breaker larger than the MOCP because a calculation suggested it; the nameplate limit governs.
The disconnecting means
Section 440.14 requires a disconnect within sight from and readily accessible from the air-conditioning or refrigerating equipment. The disconnect may be mounted on or within the equipment, but it must not be located on panels designed to allow access to the equipment, and it must not obscure the nameplate. Some exceptions exist, including one for equipment essential to an industrial process where a lockable disconnect elsewhere is used under qualified supervision. For a rooftop unit, the common answer is a fused or unfused disconnect mounted beside the unit or on its frame where the manufacturer allows.
Section 440.12 sizes the disconnect. For a hermetic compressor, the ampere rating must be at least 115% of the rated-load current or selection current, whichever is greater. A horsepower-rated switch needs an equivalent horsepower, which 440.12 tells you to find from the motor tables using the rated-load current and the locked-rotor current, taking the larger horsepower. For equipment with several motors and other loads, the ratings are combined.
Worked problem
Sizing the Copper Kettle disconnect
Find the minimum ampere rating of the disconnect for the rooftop unit, considering the compressor plus the 8.3 A of fan and blower load.
Show solution
- Compressor: 1.15 × 28.0 = 32.2 A.
- Combined with the other loads, the total current is 28.0 + 8.3 = 36.3 A; 115% of that is about 41.7 A.
- A 60 A disconnect rated for the unit's equivalent horsepower satisfies both.
Answer: At least about 41.7 A of combined rating; a 60 A switch is the usual choice.
The service receptacle
Section 210.63 requires a 125-volt, single-phase, 15- or 20-ampere receptacle within 25 feet of heating, air-conditioning and refrigeration equipment, located at an accessible location on the same level as the equipment. On a roof, that means a receptacle on the roof within 25 feet of the units, and 210.8 requires it to have ground-fault circuit-interrupter protection because it is outdoors. The receptacle may not be connected to the load side of the equipment's disconnect. The requirement exists so a service technician can plug in tools and a recovery machine without running cords from the building.
Room air conditioners and other cord-connected equipment
Part VII of Article 440 covers room air conditioners, the window and through-wall units common in apartments and small offices. For cord-and-plug-connected units, 440.62 treats the unit as a single motor unit when it meets the stated conditions, and 440.62(B) and (C) limit the unit's rating relative to the branch circuit: a room air conditioner alone on a branch circuit may not exceed 80% of the circuit rating, and where lighting or other appliances share the circuit, it may not exceed 50%. The attachment plug may serve as the disconnect. Section 440.65 requires the cord to have leakage-current detection and interruption or arc-fault protection, which is why room air conditioner plugs have the large rectangular head with a test button.
Worked problem
A window unit in the Copper Kettle office
The restaurant office will have a 120 V room air conditioner marked 11.0 A on its own 15 A circuit. Is that permitted?
Show solution
- Limit when alone on the circuit: 0.80 × 15 = 12.0 A.
- 11.0 A is within 12.0 A.
Answer: Yes, on an individual 15 A circuit.
Feeder calculations with Article 440 equipment
When rooftop units and condensing units are added to a feeder calculation, Article 220 and Article 440 work together. For load calculations, the equipment is counted at its nameplate values. For feeder conductors serving several pieces of equipment, the method parallels 430.24: the largest motor-compressor's current at 125% plus the other loads. Exam problems usually give the MCA of each unit, and a common simplification is to add the largest unit's compressor at 125% and everything else at 100%; read the question to see which data it wants you to use.
def mca(compressor_rla, others, bcsc=None):
big = max(compressor_rla, bcsc or 0)
return round(1.25 * big + sum(others), 1)
def limits(rla):
return round(1.75 * rla, 1), round(2.25 * rla, 1)
rla, fans = 28.0, [1.9, 6.4]
print("Copper Kettle RTU minimum circuit ampacity:", mca(rla, fans), "A")
print("Compressor protection limits (175%, 225%):", limits(rla), "A; nameplate MOCP governs: 70 A")
print("Disconnect, compressor alone:", round(1.15 * rla, 1), "A; with fans:", round(1.15 * (rla + sum(fans)), 1), "A")
print("Room unit limit on a 15 A circuit:", 0.80 * 15, "A alone,", 0.50 * 15, "A with other loads")Copper Kettle RTU minimum circuit ampacity: 43.3 A Compressor protection limits (175%, 225%): (49.0, 63.0) A; nameplate MOCP governs: 70 A Disconnect, compressor alone: 32.2 A; with fans: 41.7 A Room unit limit on a 15 A circuit: 12.0 A alone, 7.5 A with other loads
Breaker types and two units on one feeder
Many equipment nameplates say "maximum fuse or HACR breaker". HACR stands for heating, air-conditioning and refrigeration, and a breaker listed with that marking has been tested for group motor applications in that equipment. Most modern molded-case breakers carry the marking, but the installer must check, because 110.3(B) requires the equipment to be installed according to its listing and labeling. When the nameplate says "maximum fuse" only, a breaker may not be used for that unit.
Worked problem
A feeder to two rooftop units
The Copper Kettle's two identical rooftop units each have a 28.0 A compressor and 8.3 A of fan and blower load. Find a minimum feeder ampacity using the largest compressor at 125% and everything else at 100%.
Show solution
- Largest compressor: 1.25 × 28.0 = 35.0 A.
- Second compressor: 28.0 A.
- Fans and blowers: 2 × 8.3 = 16.6 A.
- Total: 35.0 + 28.0 + 16.6 = 79.6 A.
Answer: About 79.6 A.
Common mistakes
MistakeUsing the motor tables to size an air-conditioning compressor circuit.
InsteadUse the equipment nameplate: rated-load or selection current, MCA and MOCP.
MistakeSizing the branch conductors to the MOCP.
InsteadConductors need only the minimum circuit ampacity; the MOCP limits the fuse or breaker.
MistakeInstalling a breaker larger than the nameplate MOCP.
InsteadThe marked maximum is a limit under 440.4(B) and 110.3(B).
MistakeForgetting the service receptacle on the roof.
InsteadSection 210.63 requires a GFCI-protected receptacle within 25 ft of HVAC equipment, on the same level.
Summary and key terms
- Article 440 covers equipment with hermetic refrigerant motor-compressors and amends Article 430 for it.
- Use the rated-load current or, where marked, the larger branch-circuit selection current.
- Conductors are sized from the minimum circuit ampacity; the fuse or breaker may not exceed the maximum overcurrent protection.
- The disconnect must be within sight and readily accessible, sized at 115% of the rated-load or selection current.
- A 125 V service receptacle is required within 25 ft of HVAC equipment, on the same level, and GFCI protected outdoors.
- A cord-connected room air conditioner alone on a circuit may not exceed 80% of the circuit rating.
- Hermetic refrigerant motor-compressor
- A compressor and motor sealed in one housing and cooled by refrigerant.
- Rated-load current (RLA)
- The manufacturer's current for the compressor at rated load.
- Branch-circuit selection current (BCSC)
- A marked current, higher than RLA, used for sizing when present.
- Minimum circuit ampacity (MCA)
- The nameplate minimum conductor ampacity for packaged equipment.
- Maximum overcurrent protection (MOCP)
- The nameplate maximum rating of the branch-circuit fuse or breaker.
Practice problems
Work each problem on paper first, then reveal the answer to check.
A compressor has RLA 18 A and BCSC 21 A. Which current sizes its conductors?
Show answer
The selection current, 21 A, so at least 1.25 × 21 = 26.25 A.
A unit has a compressor RLA of 22 A and fans of 2.5 A and 4.0 A. Find its MCA.
Show answer
1.25 × 22 + 2.5 + 4.0 = 34.0 A.
A nameplate shows MCA 34 A and MOCP 50 A. What is the largest breaker permitted?
Show answer
50 A.
A room air conditioner shares a 20 A circuit with lighting. What is the largest unit rating permitted?
Show answer
0.50 × 20 = 10 A.
Lesson quiz · 5 questions
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