RAC-410 · Lesson 1 of 12 · 17 min

Large systems and central plants

In September of Theo's fourth year, Northfield won the service contract for the central plant at Riverbend Health Campus, a hospital and outpatient complex on the edge of Kitchener. Dana called Theo into her office with Raj, who would lead the chiller work. "You've spent three years on systems you can carry in a van," she said. "This one fills a basement. Raj will teach you the plant, and by spring I want you to be able to read it the way you read a split system." The contract started with a walk-through, and Raj made Theo draw the plant from memory afterwards.

This course is about chillers and the systems around them: the water-cooled and air-cooled chillers themselves, cooling towers, the chilled-water and condenser-water loops, pumps, controls, water treatment and maintenance. This first lesson describes what a central plant is, why buildings use one, and how its size and performance are measured.

From packaged units to central plants

The systems in RAC-310 to RAC-330 cooled the space they served directly: refrigerant evaporated in a coil that the air passed over. That works well up to a point. In a large building, running refrigerant lines from rooftop units to every floor becomes impractical, the charge becomes very large, and many separate machines must be maintained. A central plant separates the job into two parts. Chillers make cold water, or a water and glycol mixture, in one mechanical room, and pumps carry it through pipes to air handlers and fan coils throughout the building, where coils transfer the heat from the air to the water. The heat the chillers remove, plus the energy their compressors add, is rejected outdoors by cooling towers or air-cooled condensers.

Water is an excellent heat carrier. It holds about 3,500 times as much heat per unit volume as air for each degree of temperature change, so a pipe can move the same heat as a duct many times its size. A chilled-water system also keeps the refrigerant in one room, which makes leaks easier to find and refrigerant safety easier to manage, and lets the owner run, repair and replace the cooling equipment without entering the occupied spaces.

Central plants serve hospitals, universities, office towers, airports, data centres and district energy networks. Hospitals are typical: they need cooling all year for operating rooms, imaging equipment, laboratories and interior zones, they cannot tolerate long outages, and they usually have a staff of plant operators who keep logs and run the equipment around the clock.

The Riverbend plant

The walk-through started in the chiller room. Riverbend had three water-cooled chillers. CH-1, installed in 2009, was a 2,110 kW (600-ton) constant-speed centrifugal chiller using R-134a, with a charge of about 680 kg (1,500 lb). CH-2, installed in 2024 when the hospital added a surgical wing, was a centrifugal of the same size with a variable-speed drive, using the low-pressure refrigerant R-1233zd(E). CH-3, from 2015, was a 1,055 kW (300-ton) screw chiller using R-134a, which the operators ran at night and in the shoulder seasons. Together they could carry the plant's design load of about 3,500 kW (1,000 tons), with one large machine to spare on all but the hottest days.

The condenser water from all three went up to a three-cell cooling tower on the roof of the plant building. The chilled water left the plant through a primary-secondary piping system, which lesson 7 explains: constant-speed primary pumps, one for each chiller, circulated water through the chillers, and variable-speed secondary pumps sent it out to the buildings. A plate heat exchanger beside the chillers let the towers cool the chilled water directly in winter. In a control room at the end of the plant, the building automation system displayed the plant's temperatures, flows and alarms, and the operators' log sheets hung on a clipboard beside the screen.

Grace Adeyemi, the hospital's chief plant engineer, walked them through the operating rules. Two people from her team were on site at all times. The plant had to keep chilled water at 6.7 °C (44 °F) to the operating rooms whatever happened, and the hospital's emergency generators could carry one large chiller and its pumps if the grid failed. "Our biggest problem," she said, "is that the plant runs more chillers than the load needs, and the second chiller comes on when the first is only half loaded. We think it's the water side, but we've never had the time to prove it." Raj wrote that down. It would take most of the year to answer, and the answer is in lesson 7.

A schematic of a central chilled-water plant: three chillers in a row with their evaporators connected to a chilled-water loop that runs out to air handlers and returns, and their condensers connected to a condenser-water loop that runs up to a three-cell cooling tower; a plate heat exchanger sits between the tower loop and the chilled-water loop
The Riverbend central plant in outline: chillers, cooling tower, chilled-water and condenser-water loops and the free-cooling heat exchanger.

Units: tons, kilowatts and efficiency

Chiller capacity in Canada is usually stated in kilowatts of cooling, but North American equipment is still widely sold and discussed in tons of refrigeration, so both appear on submittals and nameplates. One ton is 12,000 Btu/h, about 3.517 kW, the cooling of melting a short ton of ice in a day.

Chiller efficiency is expressed in three common ways. The coefficient of performance, COP, is the cooling delivered divided by the electrical input, both in the same units. Energy efficiency ratio, EER, divides cooling in Btu/h by input in watts. And kilowatts per ton, kW/ton, is the electrical input divided by the cooling in tons; it is the reverse of the other two, so a lower kW/ton is better. They convert easily:

\[\text{COP} = \frac{3.517}{\text{kW/ton}}, \qquad \text{EER} = \frac{12}{\text{kW/ton}} = 3.412 \times \text{COP}\]

A modern water-cooled centrifugal chiller at its rating conditions uses about 0.16 to 0.17 kW of input per kW of cooling, a COP of about 6, or 0.55 to 0.6 kW/ton. An air-cooled chiller, rejecting heat to hotter outdoor air instead of to water from a tower, uses roughly half as much again. A complete plant also runs pumps and tower fans, so its whole-plant efficiency is worse than the chiller's alone; plant designers and operators track both.

Load, ton-hours and the shape of a year

A plant is sized for its design load, the cooling needed on a near-worst day. But a plant spends almost all of its time at part load. Riverbend's design load was about 3,500 kW, but its hours were spread over a whole year, and most of the year's cooling was done far below that. Plant energy is counted in kilowatt-hours of cooling, or ton-hours: one kilowatt-hour of cooling is 1 kW for an hour, and one ton-hour is one ton for an hour. Dividing the year's cooling by the design load gives the equivalent full-load hours, the number of hours the plant would have to run at design load to deliver the same cooling.

Grace's team had the plant's meter data, and Raj sorted it into outdoor temperature bins to see where the year's cooling actually happened. The script reproduces his summary and estimates the year's electricity, using a typical chiller efficiency and a separate allowance for pumps and towers.

# Riverbend Health Campus central plant: a year of cooling in outdoor temperature bins (illustrative)
bins = [  # (outdoor dry-bulb band, hours per year, average plant load in kW)
    ("above 30 C", 60, 3300), ("25 to 30 C", 420, 2700), ("20 to 25 C", 980, 1900),
    ("15 to 20 C", 1250, 1250), ("10 to 15 C", 1300, 800), ("below 10 C", 4750, 450)]
peak = 3517                        # kW of cooling, the plant's design load (1,000 tons)
chiller_kw_per_kw = 0.17           # chiller input per kW of cooling (COP about 5.9)
aux_kw_per_kw = 0.07               # pumps and tower fans per kW of cooling
total_cool = sum(h * q for _, h, q in bins)              # kWh of cooling in a year
print(f"hours counted {sum(h for _, h, _ in bins)}")
print(f"annual cooling {total_cool / 1e6:.2f} GWh, equivalent full-load hours {total_cool / peak:,.0f}")
for name, h, q in bins:
    print(f"{name:11s} {h:5d} h at {q:5d} kW  = {h * q / total_cool:5.1%} of the year's cooling")
chiller_kwh = total_cool * chiller_kw_per_kw
aux_kwh = total_cool * aux_kw_per_kw
print(f"chiller electricity {chiller_kwh / 1e6:.2f} GWh, pumps and towers {aux_kwh / 1e6:.2f} GWh")
print(f"whole-plant COP {1 / (chiller_kw_per_kw + aux_kw_per_kw):.2f}, chiller COP {1 / chiller_kw_per_kw:.2f}")
print(f"at 0.14 $/kWh the plant's electricity costs about ${(chiller_kwh + aux_kwh) * 0.14:,.0f} a year")
Output
hours counted 8760
annual cooling 7.93 GWh, equivalent full-load hours 2,256
above 30 C     60 h at  3300 kW  =  2.5% of the year's cooling
25 to 30 C    420 h at  2700 kW  = 14.3% of the year's cooling
20 to 25 C    980 h at  1900 kW  = 23.5% of the year's cooling
15 to 20 C   1250 h at  1250 kW  = 19.7% of the year's cooling
10 to 15 C   1300 h at   800 kW  = 13.1% of the year's cooling
below 10 C   4750 h at   450 kW  = 26.9% of the year's cooling
chiller electricity 1.35 GWh, pumps and towers 0.56 GWh
whole-plant COP 4.17, chiller COP 5.88
at 0.14 $/kWh the plant's electricity costs about $266,582 a year

The year's cooling came to about 7.9 GWh, equivalent to about 2,260 full-load hours. Only 2.5 % of it was done above 30 °C outdoors. More than a quarter was done below 10 °C, mostly by one chiller at low load or by the free-cooling heat exchanger, because the hospital's interior zones, imaging rooms and data rooms need cooling in every season. The pumps and towers added about 40 % to the chillers' electricity, which brought the whole-plant COP down from about 5.9 to about 4.2.

Two lessons follow from the numbers, and the rest of the course keeps returning to them. First, the efficiency that matters most is part-load efficiency, because that is where the plant spends its time; lesson 2 shows how part-load ratings work. Second, the auxiliaries are not small: a pump or tower fan running at full speed when it does not need to can waste as much energy as a poorly chosen chiller.

Who does what in a large plant

Large plants are a team effort, and a technician needs to know where his or her work fits. The owner's plant operators run the plant day to day: they start and stop equipment, keep logs, respond to alarms and do routine checks. A service contractor, like Northfield at Riverbend, does the preventive maintenance, repairs and annual inspections, often with the chiller manufacturer's own service technicians for major work such as compressor overhauls and controls upgrades. A water treatment company manages the chemistry of the tower and closed loops, as lesson 6 describes. A controls contractor maintains the building automation system. And consulting engineers design changes and retrofits.

In Ontario, larger refrigeration plants are also subject to TSSA's rules for operating engineers, which, depending on the plant's size and type, can require certificated operators and a chief operator, and refrigeration work itself requires the trade certificate and TSSA's requirements under CSA B52, which earlier courses described.

For Theo, the contract meant learning a new rhythm: monthly visits with Raj for inspections and log reviews, a shutdown each winter for tube cleaning and eddy current testing, the start-up of the towers each spring, and a call whenever the operators found something they could not explain. The plant was not more difficult than the systems he already knew. The same refrigeration cycle ran inside every chiller. But it was larger, more connected and more expensive to get wrong, and it rewarded patience with the logs.

The parts of a central plant and where this course covers them.
Part of the plantWhat it doesWhere in this course
ChillersRemove heat from the chilled waterLessons 2 to 4
Cooling towers and condenser waterReject the heat outdoorsLesson 5
Water treatmentPrevents scale, corrosion and biological growthLesson 6
Chilled-water pipingDelivers cold water to the coilsLesson 7
Pumps and balancingMove the water and divide it among the coilsLesson 8
Controls and sequencingDecide which machines run and at what settingsLesson 9
Operation, logs and maintenanceKeep the plant reliable and efficientLessons 10 and 11

Common mistakes

  • MistakeJudging a chiller by its full-load efficiency alone.

    InsteadCompare part-load efficiency, where the plant spends most of its hours.

  • MistakeForgetting the pumps and tower fans.

    InsteadTrack whole-plant efficiency as well as the chiller's.

  • MistakeConfusing kW/ton with COP.

    InsteadA lower kW/ton and a higher COP are both better; convert with COP = 3.517 ÷ kW/ton.

  • MistakeTreating a plant as a collection of separate machines.

    InsteadChillers, towers, pumps and coils interact; a problem in one shows up in another.

Summary and key terms

  • A central plant makes chilled water in one place and pumps it to coils throughout the buildings it serves.
  • Chillers reject the heat they remove, plus their compressor energy, through cooling towers or air-cooled condensers.
  • Capacity is stated in kilowatts or tons; one ton is 3.517 kW.
  • COP, EER and kW/ton express efficiency; COP = 3.517 ÷ kW/ton.
  • Plants spend most of their hours at part load, so part-load efficiency and auxiliaries matter.
  • Operators, service contractors, manufacturers, water treaters and controls contractors share the work.
Central plant
A room or building of chillers, pumps and heat rejection equipment that serves many coils.
Chilled water
Water cooled by chillers and pumped to coils to remove heat from air.
Ton of refrigeration
12,000 Btu/h, about 3.517 kW of cooling.
Coefficient of performance (COP)
Cooling delivered divided by energy input in the same units.
kW/ton
Electrical input in kilowatts per ton of cooling; lower is better.
Ton-hour
One ton of cooling delivered for one hour.
Equivalent full-load hours
Annual cooling divided by design load.
Design load
The cooling needed on a near-worst day, used to size the plant.

Practice problems

Work each problem on paper first, then reveal the answer to check.

  1. A chiller uses 0.50 kW/ton. What is its COP?

    Show answer

    3.517 ÷ 0.50 = about 7.0.

  2. A chiller has a COP of 6.0. What is that in kW/ton?

    Show answer

    3.517 ÷ 6.0 = about 0.59 kW/ton.

  3. A plant delivers 5.6 GWh of cooling a year with a design load of 2,800 kW. What are its equivalent full-load hours?

    Show answer

    2,000 hours.

  4. Why do hospitals need cooling in winter?

    Show answer

    Interior zones, operating rooms, imaging equipment and data rooms produce heat all year.

Lesson quiz · 5 questions

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