MATH-101 · Lesson 12 of 12 · 28 min
Calculus II in practice: case studies and a project
This course has extended calculus in three directions: techniques for evaluating integrals (Lessons 1 and 2), applications of integration to geometry, mechanics, fluids and heat (Lessons 3, 4, 6 and 11), differential equations (Lesson 5), curves described parametrically and in polar form (Lesson 7), and infinite series, from Taylor series to complex exponentials and Fourier series (Lessons 8 to 10). Real problems rarely announce which of these tools they need. This final lesson works through three case studies, each combining several lessons, and then sets a course project in which you model an engineering system of your choice with the tools of the course. The modeling cycle described at the end of Calculus I (MATH-100, Lesson 12) applies throughout: state the question and assumptions, formulate the equations, solve, check against limiting cases and data, and communicate the result.
Case study 1: draining a spherical tank
Spherical tanks store liquefied gases, water and chemicals because a sphere holds the most volume for a given surface area and resists pressure efficiently. Suppose a spherical water tank of radius \(R = 1.5\) m, initially full, must be drained for inspection through a 50 mm sharp-edged outlet at the bottom with discharge coefficient 0.61. How long will it take?
- Geometry (Lesson 3): at depth \(h\) above the bottom, the horizontal cross-section is a circle of radius \(\sqrt{2Rh - h^2}\), so its area is \(A(h) = \pi(2Rh - h^2)\).
- Flow (Lesson 5): Torricelli's law gives the outflow \(C_d a\sqrt{2gh}\), and conservation of volume gives the separable equation \(A(h)\,\dfrac{dh}{dt} = -C_d a\sqrt{2gh}\).
- Integration: separating and integrating from full (\(h = 2R\)) to empty (\(h = 0\)) gives the drain time.
Worked problem
Drain time of the spherical tank
Evaluate \(t = \dfrac{1}{C_d a\sqrt{2g}}\displaystyle\int_0^{2R}\pi(2Rh - h^2)h^{-1/2}\,dh\) for \(R = 1.5\) m.
Show solution
- Integrand: \(\pi(2Rh^{1/2} - h^{3/2})\); antiderivative \(\pi\left(\tfrac{4R}{3}h^{3/2} - \tfrac{2}{5}h^{5/2}\right)\).
- At \(h = 3\): \(\pi(2 \times 5.196 - 0.4 \times 15.588) = \pi(10.392 - 6.235) = 13.06\) m^(5/2).
- Denominator: \(0.61 \times 1.963 \times 10^{-3} \times \sqrt{19.62} = 5.30 \times 10^{-3}\) m^(5/2)/s.
- \(t = 13.06 / 5.30 \times 10^{-3} = 2{,}460\) s.
Answer: About 41 minutes. A check: the tank holds (4/3)π(1.5)³ = 14.1 m³, and the initial outflow from 3 m of head is 0.61 × 1.963 × 10⁻³ × √(58.9) = 9.2 L/s, which would empty it in 26 minutes if sustained; the actual time is longer because the outflow slows as the head falls. The integral can also give the time to drain to any intermediate level, which operators need to plan the work.
Case study 2: the ripple of a rectified supply
An AC-to-DC power supply first rectifies the mains voltage. A full-wave rectifier produces \(|V_p\sin\omega t|\), which has a large DC component but also large ripple. To design the filter that smooths it, the engineer needs to know how much of each frequency is present, a Fourier series problem (Lesson 10).
Worked problem
Fourier series of a full-wave rectified sine
Find the DC component and the amplitude of the first ripple harmonic of \(f(t) = |\sin t|\), and apply them to a 120 V RMS, 60 Hz supply.
Show solution
- The period is \(\pi\), so \(\omega_0 = 2\) and the harmonics are \(\cos 2kt\) (the function is even, so there are no sine terms).
- DC: \(a_0 = \dfrac{1}{\pi}\displaystyle\int_0^{\pi}\sin t\,dt = \dfrac{2}{\pi}\).
- \(a_k = \dfrac{2}{\pi}\displaystyle\int_0^{\pi}\sin t\cos 2kt\,dt\). Using \(\sin A\cos B = \tfrac{1}{2}[\sin(A + B) + \sin(A - B)]\) (Lesson 1): \(a_k = -\dfrac{4}{\pi(4k^2 - 1)}\).
- For \(V_p = 170\) V: DC \(= 2 \times 170/\pi = 108\) V; the first harmonic (\(k = 1\), at 120 Hz) has amplitude \(4 \times 170/(3\pi) = 72.2\) V; the next (240 Hz) has \(4 \times 170/(15\pi) = 14.4\) V.
Answer: A DC level of 108 V with 72 V of 120 Hz ripple. To reduce the ripple to 1 V with a second-order LC filter, whose attenuation rises at 40 dB per decade, the filter's corner frequency must satisfy (120/f_c)² ≈ 72, giving f_c ≈ 14 Hz. In practice large capacitors hold the voltage near the peak instead, but the harmonic analysis explains why the rectifier draws pulsed current rich in harmonics (ELE-470).
Case study 3: the length of a suspension cable
The main cables of a suspension bridge, which carry a nearly uniform load per horizontal meter, hang in a parabola. Engineers need the cable length to order the cable and to compute how much it stretches under load. For a span \(L\) with sag \(s\) at midspan, the cable is \(y = 4sx^2/L^2\) for \(-L/2 \le x \le L/2\), and its length is the arc length integral (Lesson 3):
This integral can be done exactly with a trigonometric or hyperbolic substitution (Lesson 2), but the result is cumbersome. Engineers instead expand the square root with the binomial series (Lesson 9), \(\sqrt{1 + u} \approx 1 + \tfrac{u}{2} - \tfrac{u^2}{8}\), and integrate term by term:
Worked problem
Cable length
A suspension bridge has a main span of 1,000 m and a sag of 100 m. Estimate the cable length with one and two correction terms, and compare with the exact value of 1,026.06 m obtained by numerical integration.
Show solution
- \(s/L = 0.1\). One correction term: \(S \approx 1000(1 + 0.02667) = 1{,}026.67\) m.
- Two terms: \(1000(1 + 0.02667 - 0.00064) = 1{,}026.03\) m.
Answer: The two-term estimate is within 3 cm of the exact 1,026.06 m over a kilometer, and even the one-term estimate errs by only 0.6 m. The series also shows how sensitive the sag is to small changes in cable length (from temperature or load): differentiating S with respect to s gives dS ≈ (16/3)(s/L) ds, so a 1 m change in sag changes the length by only about 0.53 m. Equivalently, a small extension of the cable produces a much larger change in sag, which is why bridge decks rise and fall noticeably with temperature.
Common threads
The case studies share several lessons for practice. Each combined two or three topics from the course, so the ability to recognize which tools a problem needs matters as much as skill with any single technique. Each involved an approximation or an assumption (Torricelli flow, ideal rectification, a parabolic cable) that should be stated and checked. Each result was checked against a simpler estimate: the initial outflow rate, the size of the harmonics, the exact numerical length. And each answer was interpreted in terms of what an engineer would do with it: plan a drain-down, design a filter, order a cable.
The course project
Choose one of the following problems, or propose your own of similar scope with your instructor's approval, and write a technical report of about eight pages including figures.
- Project A: A storage tank. Choose a tank shape (horizontal cylinder, sphere, cone or cylinder with hemispherical ends). Derive its volume as a function of liquid depth (Lessons 2 and 3) and produce a gauge chart. Find the centroid of the liquid at several depths (Lesson 4) and the time to drain through a specified outlet (Lesson 5). Compare a Simpson's rule estimate of one integral with its exact value.
- Project B: A periodic signal. Choose a periodic waveform from engineering practice (a PWM output, a rectifier current, a cam lift profile, a daily temperature cycle). Compute its Fourier coefficients (Lesson 10), plot partial sums, find its RMS value and harmonic distortion using Parseval's theorem, and design a simple filter or analyze the response of a first-order system to it (Lessons 5 and 9).
- Project C: A structural or thermal element. Analyze a beam with a non-uniform load, or insulation on a pipe or tank, from first principles (Lesson 11): set up the governing integral or differential equation, solve it, check limiting cases, and investigate how the result depends on the main design parameters. Include a series approximation (Lesson 9) of a key result and assess its accuracy.
- Project D: A curve in design. Model a cam profile, a gear tooth, a road transition curve or a suspension cable with parametric or polar equations (Lesson 7); compute slopes, curvature-related quantities, arc length and enclosed area; and compare exact, series and numerical evaluations of any integral that has no elementary form.
Every report should state the problem and assumptions, derive the equations, present the calculations clearly with units, include at least two graphs, check results against limiting cases or independent estimates, analyze sensitivity to at least two parameters, and discuss limitations. Where you use software to evaluate integrals or sums, show that you have verified its results by hand calculation, differentiation or convergence checks.
Working with software
Each case study could be done in minutes with mathematical software, and engineers routinely use computer algebra, spreadsheets and numerical libraries for this kind of work. Software changes what an engineer must be good at, not whether calculus matters. Someone must set up the right integral or equation, choose sensible units and parameters, recognize when a result is implausible, and know which approximations are being made. In the spherical tank problem, for example, software would integrate whatever area function it was given; only an engineer who understands the geometry would notice an area formula that went negative above the equator. A practical workflow is to sketch the expected behavior first, compute with software, then check the output against a hand estimate, a limiting case or an independent method, and record the inputs so that others can reproduce the result. The course project asks for exactly this combination of analysis, computation and checking.
Looking ahead
The tools of this course carry directly into the second year of an engineering program. Multivariable calculus (MATH-209) extends integration to areas, volumes and surfaces in two and three dimensions, where the element method of Lessons 3, 4 and 11 becomes double and triple integrals. Differential equations (MATH-201) builds on Lesson 5 and on the complex exponentials of Lesson 9 to treat vibrations, circuits and control systems, and introduces the Laplace transform previewed in Lesson 6. Numerical methods (MATH-300) develops the numerical integration and series approximations used here into general algorithms. And the Fourier series of Lesson 10 lead to the Fourier transform in signals and systems. Calculus is not finished when this course ends: it becomes the language in which engineering is done.
Common mistakes
MistakeUsing a constant cross-section for a tank whose area changes with depth.
InsteadWrite A(h) from the geometry and keep it inside the integral.
MistakeTreating the DC level of a rectified supply as its RMS value.
InsteadCompute the average (2Vp/π) and RMS separately; ripple harmonics add to the RMS.
MistakeTruncating a series without estimating the error.
InsteadCompare with the next term, an exact value or a numerical integral.
MistakeTrusting software results without checks.
InsteadVerify by differentiation, limiting cases or an independent estimate.
MistakeReporting a result without interpreting it.
InsteadState what the number means for the engineering decision.
Summary and key terms
- Real problems combine several topics; recognizing the tools needed is a key skill.
- A spherical tank drains according to a separable equation with A(h) = π(2Rh − h²); the 1.5 m tank takes about 41 minutes.
- A full-wave rectified sine has DC 2Vp/π and even harmonics with amplitudes 4Vp/(π(4k² − 1)).
- A parabolic cable's length follows from the arc length integral, approximated by a binomial series.
- Every result should be checked against a simpler estimate and interpreted for the decision it supports.
- The course project applies integration, differential equations, series and parametric curves to a system of your choice.
- Calculus II leads to multivariable calculus, differential equations, numerical methods and signal analysis.
- Gauge chart
- A table converting liquid depth in a tank to volume.
- Head
- The height of liquid above an outlet, which drives the outflow.
- Full-wave rectifier
- A circuit that converts AC to a unidirectional voltage |Vp sin ωt|.
- Ripple
- The AC component remaining in a rectified DC voltage.
- Corner frequency
- The frequency at which a filter begins to attenuate.
- Sag
- The vertical distance from a cable's supports to its lowest point.
- Binomial approximation
- Truncating the binomial series to a few terms.
- Sensitivity
- The rate at which an output changes with an input.
- Verification
- Checking a result by an independent method.
- Modeling cycle
- The iterative process of formulating, solving, checking and refining a model.
Practice problems
Work each problem on paper first, then reveal the answer to check.
Write the cross-sectional area of a spherical tank of radius 2 m at depth h.
Show answer
A(h) = π(4h − h²).
Volume of liquid in a sphere of radius R filled to depth h?
Show answer
πh²(3R − h)/3.
What fraction of a sphere's volume is below half its height?
Show answer
One half, by symmetry.
DC value of a full-wave rectified 340 V peak sine?
Show answer
2 × 340/π ≈ 216 V.
Ratio of the 240 Hz to 120 Hz ripple amplitudes for a full-wave rectified 60 Hz sine?
Show answer
(1/15)/(1/3) = 1/5.
Why does a full-wave rectified sine contain only even harmonics of 60 Hz?
Show answer
Its period is half the mains period, so its harmonics are multiples of 120 Hz.
One-term cable length for a 500 m span with 40 m sag?
Show answer
500(1 + 8/3 × 0.0064) = 508.5 m.
By how much does the cable length change if the sag of the 1,000 m bridge increases by 2 m?
Show answer
About (16/3)(0.1)(2) ≈ 1.07 m.
Name two checks you could make on a computed drain time.
Show answer
Compare with volume/initial outflow, check units, test a simpler geometry, compare with measurement.
Which course extends the element method to double and triple integrals?
Show answer
MATH-209, Multivariable Calculus.
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